QAccessibleDisplay: don't use a container for just one element
Drop the use of QVLA, and the loop. Put all of the code into QT_NO_SHORTCUT. Change-Id: I49b8e9aa403ea793fd2f3701a521776c33b64a3c Reviewed-by: Edward Welbourne <edward.welbourne@qt.io>
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@ -462,21 +462,15 @@ QVector<QPair<QAccessibleInterface*, QAccessible::Relation> >
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QAccessibleDisplay::relations(QAccessible::Relation match /* = QAccessible::AllRelations */) const
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{
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QVector<QPair<QAccessibleInterface*, QAccessible::Relation> > rels = QAccessibleWidget::relations(match);
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if (match & QAccessible::Labelled) {
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QVarLengthArray<QObject *, 4> relatedObjects;
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#ifndef QT_NO_SHORTCUT
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if (match & QAccessible::Labelled) {
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if (QLabel *label = qobject_cast<QLabel*>(object())) {
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relatedObjects.append(label->buddy());
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}
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#endif
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for (int i = 0; i < relatedObjects.count(); ++i) {
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const QAccessible::Relation rel = QAccessible::Labelled;
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QAccessibleInterface *iface = QAccessible::queryAccessibleInterface(relatedObjects.at(i));
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if (iface)
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if (QAccessibleInterface *iface = QAccessible::queryAccessibleInterface(label->buddy()))
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rels.append(qMakePair(iface, rel));
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}
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}
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#endif
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return rels;
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}
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