Simplify creating QCFTypes from CFTypeRefs
Instead of forcing the user to cast: QCFType<CFFooRef> foo = (CFFooRef)CFFunctionReturningCFTypeRef()); We can do it for them, since we already know the expected type: auto foo = QCFType<CFFooRef>(CFFunctionReturningCFTypeRef)); Change-Id: I994d5d6530f220288b4bfd6ab16eae9f159ce3ef Reviewed-by: Thiago Macieira <thiago.macieira@intel.com> Reviewed-by: Tor Arne Vestbø <tor.arne.vestbo@qt.io>
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@ -137,8 +137,10 @@ private:
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template <typename T>
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class QCFType : public QAppleRefCounted<T, CFTypeRef, CFRetain, CFRelease>
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{
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using Base = QAppleRefCounted<T, CFTypeRef, CFRetain, CFRelease>;
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public:
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using QAppleRefCounted<T, CFTypeRef, CFRetain, CFRelease>::QAppleRefCounted;
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using Base::Base;
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explicit QCFType(CFTypeRef r) : Base(static_cast<T>(r)) {}
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template <typename X> X as() const { return reinterpret_cast<X>(this->value); }
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static QCFType constructFromGet(const T &t)
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{
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@ -151,6 +153,7 @@ public:
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class Q_CORE_EXPORT QCFString : public QCFType<CFStringRef>
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{
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public:
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using QCFType<CFStringRef>::QCFType;
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inline QCFString(const QString &str) : QCFType<CFStringRef>(0), string(str) {}
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inline QCFString(const CFStringRef cfstr = 0) : QCFType<CFStringRef>(cfstr) {}
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inline QCFString(const QCFType<CFStringRef> &other) : QCFType<CFStringRef>(other) {}
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