Use u' ' instead of QLatin1Char(' ') in qkeysequence.cpp
Easier on the eye. Amends ada885dfd55d5c386d04039babee43e49ccab5c5. Pick-to: 6.9 6.8 Change-Id: Id218288ccc4556abb7c9a199f27b7dcb6a3ba73e Reviewed-by: Marc Mutz <marc.mutz@qt.io>
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@ -1107,7 +1107,7 @@ QKeyCombination QKeySequencePrivate::decodeString(QString accel, QKeySequence::S
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qsizetype lastI = 0;
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while ((i = sl.indexOf(u'+', i + 1)) != -1) {
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QStringView sub = QStringView{ sl }.mid(lastI, i - lastI + 1);
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while (sub.size() > 1 && sub.at(0) == QLatin1Char(' ')) {
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while (sub.size() > 1 && sub.at(0) == u' ') {
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sub = sub.mid(1);
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++lastI;
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}
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@ -1143,7 +1143,7 @@ QKeyCombination QKeySequencePrivate::decodeString(QString accel, QKeySequence::S
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if (!validModifier) {
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// Try harder with slower code that trims spaces
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const QString cleanedSub = sub.toString().remove(QLatin1Char(' '));
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const QString cleanedSub = sub.toString().remove(u' ');
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validModifier = identifyModifier(cleanedSub);
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}
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if (!validModifier)
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@ -1157,9 +1157,9 @@ QKeyCombination QKeySequencePrivate::decodeString(QString accel, QKeySequence::S
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if (p > 0)
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accelRef = accelRef.mid(p + 1);
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while (accelRef.size() > 1 && accelRef.at(0) == QLatin1Char(' '))
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while (accelRef.size() > 1 && accelRef.at(0) == u' ')
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accelRef = accelRef.mid(1);
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while (accelRef.size() > 1 && accelRef.endsWith(QLatin1Char(' ')))
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while (accelRef.size() > 1 && accelRef.endsWith(u' '))
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accelRef.chop(1);
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int fnum = 0;
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