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QDebug: remove QPair streaming docs

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QPair _is_ std::pair. If this wasn't a fake-definition under #ifdef
Q_QDOC, the compiler would have complained long ago.

Pick-to: 6.5
Change-Id: Idfe589ff13115d3d908572a17b849f634ec86787
Reviewed-by: Ivan Solovev <ivan.solovev@qt.io>
(cherry picked from commit 9d54b5c57e6f8d8a7fee160ed899809135cd5866)
Reviewed-by: Qt Cherry-pick Bot <cherrypick_bot@qt-project.org>
This commit is contained in:
Marc Mutz 2023-12-07 11:45:50 +01:00 committed by Qt Cherry-pick Bot
parent f1ceddde07
commit cfb44f3b3c
2 changed files with 0 additions and 11 deletions
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8
src/corelib/io/qdebug.cpp
View File

@ -979,14 +979,6 @@ QDebug &QDebug::resetFormat()
\c T need to support streaming into QDebug.
*/
/*!
\fn template <class T1, class T2> QDebug operator<<(QDebug debug, const QPair<T1, T2> &pair)
\relates QDebug
Writes the contents of \a pair to \a debug. Both \c T1 and
\c T2 need to support streaming into QDebug.
*/
/*!
\fn template <class T1, class T2> QDebug operator<<(QDebug debug, const std::pair<T1, T2> &pair)
\relates QDebug

3
src/corelib/io/qdebug.h
View File

@ -420,9 +420,6 @@ QDebug operator<<(QDebug debug, const QMultiHash<Key, T> &hash);
template <typename T>
QDebug operator<<(QDebug debug, const QSet<T> &set);
template <class T1, class T2>
QDebug operator<<(QDebug debug, const QPair<T1, T2> &pair);
template <class T1, class T2>
QDebug operator<<(QDebug debug, const std::pair<T1, T2> &pair);