QKeyCombination: code tidies
* Use the new QFlags::toInt() instead of an explicit cast. * Don't apply ~ to an enumerator and then convert the result to an int; instead, convert the enumerator to int and then bitwise negate it. The former is going to break in an upcoming commit. Change-Id: I3a798d61452891d2f61f84e2d8e17237f47c5659 Reviewed-by: Volker Hilsheimer <volker.hilsheimer@qt.io>
This commit is contained in:
parent
d95e39a9b8
commit
9c89743d72
@ -1874,11 +1874,11 @@ public:
|
|||||||
{}
|
{}
|
||||||
|
|
||||||
constexpr explicit QKeyCombination(Qt::Modifiers modifiers, Qt::Key key = Qt::Key_unknown) noexcept
|
constexpr explicit QKeyCombination(Qt::Modifiers modifiers, Qt::Key key = Qt::Key_unknown) noexcept
|
||||||
: combination(int(modifiers) | int(key))
|
: combination(modifiers.toInt() | int(key))
|
||||||
{}
|
{}
|
||||||
|
|
||||||
constexpr explicit QKeyCombination(Qt::KeyboardModifiers modifiers, Qt::Key key = Qt::Key_unknown) noexcept
|
constexpr explicit QKeyCombination(Qt::KeyboardModifiers modifiers, Qt::Key key = Qt::Key_unknown) noexcept
|
||||||
: combination(int(modifiers) | int(key))
|
: combination(modifiers.toInt() | int(key))
|
||||||
{}
|
{}
|
||||||
|
|
||||||
constexpr Qt::KeyboardModifiers keyboardModifiers() const noexcept
|
constexpr Qt::KeyboardModifiers keyboardModifiers() const noexcept
|
||||||
@ -1888,7 +1888,7 @@ public:
|
|||||||
|
|
||||||
constexpr Qt::Key key() const noexcept
|
constexpr Qt::Key key() const noexcept
|
||||||
{
|
{
|
||||||
return Qt::Key(combination & ~Qt::KeyboardModifierMask);
|
return Qt::Key(combination & ~int(Qt::KeyboardModifierMask));
|
||||||
}
|
}
|
||||||
|
|
||||||
static constexpr QKeyCombination fromCombined(int combined)
|
static constexpr QKeyCombination fromCombined(int combined)
|
||||||
|
Loading…
x
Reference in New Issue
Block a user