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tst_QWinEventNotifier: fix flakiness

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disableNotifiersInActivatedSlot(disable_signaled2) fails, if a signaled
state of the event #2 is detected prior to the event #1. In this case,
we get a timeout on waiting for event #1 which was disabled by the
first notification.

So, accept a disabled state of the notifier in condition for successful
exit from the loop.

Change-Id: I8a2fe76f8ec9362556d1ca1fe0be39a93ed58977
Reviewed-by: Joerg Bornemann <joerg.bornemann@qt.io>
This commit is contained in:
Alex Trotsenko 2018-03-21 19:29:39 +02:00
parent 69948f4899
commit 927db42882
1 changed files with 7 additions and 3 deletions
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10
tests/auto/corelib/kernel/qwineventnotifier/tst_qwineventnotifier.cpp
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@ -125,6 +125,7 @@ public:
HANDLE eventHandle() const { return notifier.handle(); }
int numberOfTimesActivated() const { return activatedCount; }
void setEnabled(bool b) { notifier.setEnabled(b); }
bool isEnabled() const { return notifier.isEnabled(); }
signals:
void activated();
@ -218,8 +219,9 @@ void tst_QWinEventNotifier::disableNotifiersInActivatedSlot()
for (int i = 0; i < count; ++i)
events[i].reset(new EventWithNotifier);
auto isActivatedOrNull = [&events](int i) {
return !events.at(i) || events.at(i)->numberOfTimesActivated() > 0;
auto isActivatedOrDisabled = [&events](int i) {
return !events.at(i) || !events.at(i)->isEnabled()
|| events.at(i)->numberOfTimesActivated() > 0;
};
for (auto &e : events) {
@ -230,8 +232,10 @@ void tst_QWinEventNotifier::disableNotifiersInActivatedSlot()
else
events.at(i)->setEnabled(false);
}
if (std::all_of(notifiersToSignal.begin(), notifiersToSignal.end(), isActivatedOrNull))
if (std::all_of(notifiersToSignal.begin(), notifiersToSignal.end(),
isActivatedOrDisabled)) {
QTimer::singleShot(0, &QTestEventLoop::instance(), SLOT(exitLoop()));
}
});
}
for (int i : notifiersToSignal)