macOS: Don't assume NSEvent charactersByApplyingModifiers: produces character

In cases where the keyboard layout doesn't have a mapping for a given
event and modifier combination the result will be an empty string.

Fixes: QTBUG-90683
Change-Id: Ice06241f0ae71a19cde041410818decc312bc630
Reviewed-by: Morten Johan Sørvig <morten.sorvig@qt.io>
(cherry picked from commit 7c85a45fde5dd3f84eb033261ccb0d54ee72d30c)
Reviewed-by: Tor Arne Vestbø <tor.arne.vestbo@qt.io>
This commit is contained in:
Tor Arne Vestbø 2021-01-27 18:40:12 +01:00
parent 952635dabe
commit 7bdb824b2f

View File

@ -527,8 +527,11 @@ const QAppleKeyMapper::KeyMap &QAppleKeyMapper::keyMapForKey(VirtualKeyCode virt
// compare the results to Cocoa.
auto cocoaModifiers = toCocoaModifiers(qtModifiers);
auto *charactersWithModifiers = [NSApp.currentEvent charactersByApplyingModifiers:cocoaModifiers];
Q_ASSERT(charactersWithModifiers && charactersWithModifiers.length > 0);
auto cocoaUnicodeKey = QChar([charactersWithModifiers characterAtIndex:0]);
QChar cocoaUnicodeKey;
if (charactersWithModifiers.length > 0)
cocoaUnicodeKey = QChar([charactersWithModifiers characterAtIndex:0]);
if (cocoaUnicodeKey != carbonUnicodeKey) {
qCWarning(lcQpaKeyMapper) << "Mismatch between Cocoa" << cocoaUnicodeKey
<< "and Carbon" << carbonUnicodeKey << "for virtual key" << virtualKey