Avoid mixing atomic futex changes and QAtomic
Either the mix of futex and atomic, or the mix of 32-bit futex and 64-bit atomic doesn't work. In any case, the existing code leads to bad behavior. Fixes: QTBUG-92188 Change-Id: Icc6ba28d6e2465c373d00e84f4da2b92c037e797 Reviewed-by: Qt CI Bot <qt_ci_bot@qt-project.org> Reviewed-by: Mårten Nordheim <marten.nordheim@qt.io> (cherry picked from commit 2d9cc639a4a7a5e97979a6034364bd67dfa10c23) Reviewed-by: Allan Sandfeld Jensen <allan.jensen@qt.io>
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@ -358,47 +358,31 @@ void QSemaphore::release(int n)
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quintptr prevValue = u.fetchAndAddRelease(nn);
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if (futexNeedsWake(prevValue)) {
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#ifdef FUTEX_OP
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if (!futexHasWaiterCount) {
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/*
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On 32-bit systems, all waiters are waiting on the same address,
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so we'll wake them all and ask the kernel to clear the high bit.
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atomic {
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int oldval = u;
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u = oldval & ~(1 << 31);
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futexWake(u, INT_MAX);
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if (oldval == 0) // impossible condition
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futexWake(u, INT_MAX);
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}
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*/
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quint32 op = FUTEX_OP_ANDN | FUTEX_OP_OPARG_SHIFT;
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quint32 oparg = 31;
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quint32 cmp = FUTEX_OP_CMP_EQ;
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quint32 cmparg = 0;
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futexWakeOp(u, INT_MAX, INT_MAX, u, FUTEX_OP(op, oparg, cmp, cmparg));
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} else {
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if (futexHasWaiterCount) {
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/*
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On 64-bit systems, the single-token waiters wait on the low half
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and the multi-token waiters wait on the upper half. So we ask
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the kernel to wake up n single-token waiters and all multi-token
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waiters (if any), then clear the multi-token wait bit.
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waiters (if any), and clear the multi-token wait bit.
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atomic {
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int oldval = *upper;
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*upper = oldval & ~(1 << 31);
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*upper = oldval | 0;
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futexWake(lower, n);
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if (oldval < 0) // sign bit set
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if (oldval != 0) // always true
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futexWake(upper, INT_MAX);
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}
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*/
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quint32 op = FUTEX_OP_ANDN | FUTEX_OP_OPARG_SHIFT;
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quint32 oparg = 31;
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quint32 cmp = FUTEX_OP_CMP_LT;
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quint32 op = FUTEX_OP_OR;
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quint32 oparg = 0;
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quint32 cmp = FUTEX_OP_CMP_NE;
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quint32 cmparg = 0;
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u.fetchAndAndRelease(futexNeedsWakeAllBit - 1);
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futexWakeOp(*futexLow32(&u), n, INT_MAX, *futexHigh32(&u), FUTEX_OP(op, oparg, cmp, cmparg));
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return;
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}
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#else
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// Unset the bit and wake everyone. There are two possibibilies
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#endif
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// Unset the bit and wake everyone. There are two possibilities
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// under which a thread can set the bit between the AND and the
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// futexWake:
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// 1) it did see the new counter value, but it wasn't enough for
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@ -406,8 +390,12 @@ void QSemaphore::release(int n)
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// 2) it did not see the new counter value, in which case its
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// futexWait will fail.
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u.fetchAndAndRelease(futexNeedsWakeAllBit - 1);
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if (futexHasWaiterCount) {
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futexWakeAll(*futexLow32(&u));
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futexWakeAll(*futexHigh32(&u));
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} else {
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futexWakeAll(u);
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#endif
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}
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}
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return;
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}
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