Fix Intel compiler warning about change of sign
The variable c is unsigned, so the second operand is unsigned, constraing the -1 to be unsigned too and causing a change of sign. Instead, cast the middle operations to int, as that's the return value anyway. error #68: integer conversion resulted in a change of sign Change-Id: I1a800c709d3543699131ffff13c2fd79f14f8b43 Reviewed-by: Olivier Goffart (Woboq GmbH) <ogoffart@woboq.com> Reviewed-by: Marc Mutz <marc.mutz@kdab.com>
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@ -63,9 +63,9 @@ Q_DECL_CONSTEXPR inline char toHexLower(uint value) Q_DECL_NOTHROW
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Q_DECL_CONSTEXPR inline int fromHex(uint c) Q_DECL_NOTHROW
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{
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return ((c >= '0') && (c <= '9')) ? c - '0' :
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((c >= 'A') && (c <= 'F')) ? c - 'A' + 10 :
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((c >= 'a') && (c <= 'f')) ? c - 'a' + 10 :
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return ((c >= '0') && (c <= '9')) ? int(c - '0') :
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((c >= 'A') && (c <= 'F')) ? int(c - 'A' + 10) :
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((c >= 'a') && (c <= 'f')) ? int(c - 'a' + 10) :
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/* otherwise */ -1;
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}
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@ -76,7 +76,7 @@ Q_DECL_CONSTEXPR inline char toOct(uint value) Q_DECL_NOTHROW
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Q_DECL_CONSTEXPR inline int fromOct(uint c) Q_DECL_NOTHROW
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{
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return ((c >= '0') && (c <= '7')) ? c - '0' : -1;
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return ((c >= '0') && (c <= '7')) ? int(c - '0') : -1;
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}
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}
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