QMenu: Accept accelerators typed on keypad

Add Qt::KeypadModifier (and the combination with Qt::AltModifier) to the
modifiers that may be set in a key event in order to trigger a menu
action via its accelerator.

Otherwise, an action that has a number set as the accelerator (e.g.
using text "&1 Exit"), cannot be triggered by typing the corresponding
number on the keypad.

Fixes: QTBUG-73390
Change-Id: I0fa63b0c5f23823c61e159fcc72f7245215f8aae
Reviewed-by: Axel Spoerl <axel.spoerl@qt.io>
(cherry picked from commit ca4334bc966c7e5f9997f98b83afe37eb8b1d3ba)
Reviewed-by: Qt Cherry-pick Bot <cherrypick_bot@qt-project.org>
(cherry picked from commit b5ba125fa07c71dfbd5ce0d62b946c232106f91b)
This commit is contained in:
Michael Weghorn 2024-12-12 08:39:33 +01:00 committed by Qt Cherry-pick Bot
parent 595a557776
commit 5c36926f6b

View File

@ -3363,8 +3363,11 @@ void QMenu::keyPressEvent(QKeyEvent *e)
}
if (!key_consumed) { // send to menu bar
if ((!e->modifiers() || e->modifiers() == Qt::AltModifier || e->modifiers() == Qt::ShiftModifier) &&
e->text().size()==1) {
const Qt::KeyboardModifiers modifiers = e->modifiers();
if ((!modifiers || modifiers == Qt::AltModifier || modifiers == Qt::ShiftModifier
|| modifiers == Qt::KeypadModifier
|| modifiers == (Qt::KeypadModifier | Qt::AltModifier))
&& e->text().size() == 1) {
bool activateAction = false;
QAction *nextAction = nullptr;
if (style()->styleHint(QStyle::SH_Menu_KeyboardSearch, nullptr, this) && !e->modifiers()) {