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QString::lastIndexOf: fix off-by-one for zero length matches

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Otherwise, it would report that lastIndexOf of an empty pattern
in an empty string doesn't exist. Next commit adds extensive autotests;
for now, disable a broken autotest (which already features a comment
about why it's broken).

Change-Id: I9a0e5c0142007f81f5cf93e356c8bd82f00066f7
Reviewed-by: Thiago Macieira <thiago.macieira@intel.com>
(cherry picked from commit be83ff65c424cff1036e7da19d6175826d9f7ed9)
This commit is contained in:
Giuseppe D'Angelo 2020-12-07 23:42:33 +01:00
parent be0301b42f
commit 3a273ac47f
2 changed files with 3 additions and 3 deletions
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4
src/corelib/text/qstring.cpp
View File

@ -4558,13 +4558,13 @@ int QString::lastIndexOf(const QRegularExpression &re, int from, QRegularExpress
return -1;
}
int endpos = (from < 0) ? (size() + from + 1) : (from + 1);
int endpos = (from < 0) ? (size() + from + 1) : (from);
QRegularExpressionMatchIterator iterator = re.globalMatch(*this);
int lastIndex = -1;
while (iterator.hasNext()) {
QRegularExpressionMatch match = iterator.next();
int start = match.capturedStart();
if (start < endpos) {
if (start <= endpos) {
lastIndex = start;
if (rmatch)
*rmatch = std::move(match);

2
tests/auto/corelib/text/qstring/tst_qstring.cpp
View File

@ -1674,7 +1674,7 @@ void tst_QString::lastIndexOf()
QCOMPARE(haystack.lastIndexOf(needle.toLatin1(), from, cs), expected);
QCOMPARE(haystack.lastIndexOf(needle.toLatin1().data(), from, cs), expected);
if (from >= -1 && from < haystack.size()) {
if (from >= -1 && from < haystack.size() && needle.size() > 0) {
// unfortunately, QString and QRegExp don't have the same out of bound semantics
// I think QString is wrong -- See file log for contact information.
{