QVariant::fromValue<T>: require T to be copy constructible
In Qt 5, QVariant::fromValue<T> would not compile unless Q_DECLARE_METATYPE(T) was used, and Q_DECLARE_METATYPE(T) would lead to a compile error if T were not copy constructible. In Qt 6, we do not require Q_DECLARE_METATYPE before using fromValue, and QMetaType itself works with non-copy constructible types just fine. However, QVariant still requires it, thus we need to now enforce this in fromValue itself. Change-Id: Ib6964a438d8c46033dd3a037b9d871de2b42e175 Reviewed-by: Lars Knoll <lars.knoll@qt.io>
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@ -392,7 +392,12 @@ class Q_CORE_EXPORT QVariant
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}
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template<typename T>
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#ifndef Q_CLANG_QDOC
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static inline auto fromValue(const T &value) ->
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std::enable_if_t<std::is_copy_constructible_v<T>, QVariant>
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#else
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static inline QVariant fromValue(const T &value)
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#endif
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{
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return QVariant(QMetaType::fromType<T>(), std::addressof(value));
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}
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@ -68,6 +68,21 @@
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class CustomNonQObject;
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template<typename T, typename = void>
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struct QVariantFromValueCompiles
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{
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static inline constexpr bool value = false;
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};
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template<typename T>
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struct QVariantFromValueCompiles<T, std::void_t<decltype (QVariant::fromValue(std::declval<T>()))>>
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{
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static inline constexpr bool value = true;
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};
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static_assert(QVariantFromValueCompiles<int>::value);
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static_assert(!QVariantFromValueCompiles<QObject>::value);
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class tst_QVariant : public QObject
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{
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Q_OBJECT
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