Deprecate QtFuture::makeReadyFuture()
[ChangeLog][Deprecation Notice][QtCore] The QtFuture::makeReadyFuture() method and all its specializations are deprecated since Qt 6.10. The reason for the deprecation is that the method has a makeReadyFuture(const QList<T> &) overload, which behaves differently from all other overloads (including other non-const ref QList overloads). Use QtFuture::makeReadyVoidFuture() when you need a ready void QFuture, or QtFuture::makeReadyValueFuture() when you need to propagate the input type to the returned QFuture, or QtFuture::makeReadyRangeFuture() when you need to create a multi-value future based on an input container. Fixes: QTBUG-109677 Change-Id: I55125269989df0a02840d5ddd5763ef5f1070df5 Reviewed-by: Qt CI Bot <qt_ci_bot@qt-project.org> Reviewed-by: Marc Mutz <marc.mutz@qt.io>
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@ -522,15 +522,18 @@ QFuture<std::variant<std::decay_t<Futures>...>> whenAny(Futures &&... futures);
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#endif // Q_QDOC
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#if QT_DEPRECATED_SINCE(6, 10)
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#if defined(Q_QDOC)
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static QFuture<void> makeReadyFuture()
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#else
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template<typename T = void>
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QT_DEPRECATED_VERSION_X(6, 10, "Use makeReadyVoidFuture() instead")
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static QFuture<T> makeReadyFuture()
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#endif
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{
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return makeReadyVoidFuture();
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}
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#endif // QT_DEPRECATED_SINCE(6, 10)
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} // namespace QtFuture
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@ -973,6 +973,12 @@
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\since 6.1
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\overload
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\deprecated [6.10] Use makeReadyValueFuture() instead
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The QtFuture::makeReadyFuture() method should be avoided because it has an
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inconsistent set of overloads. It will be deprecated in future Qt releases.
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Use QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture() or
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QtFuture::makeReadyRangeFuture() instead.
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Creates and returns a QFuture which already has a result \a value.
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The returned QFuture has a type of std::decay_t<T>, where T is not void.
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@ -992,6 +998,12 @@
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\since 6.1
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\overload
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\deprecated [6.10] Use makeReadyVoidFuture() instead
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The QtFuture::makeReadyFuture() method should be avoided because it has an
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inconsistent set of overloads. It will be deprecated in future Qt releases.
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Use QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture() or
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QtFuture::makeReadyRangeFuture() instead.
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Creates and returns a void QFuture. Such QFuture can't store any result.
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One can use it to query the state of the computation.
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@ -1015,6 +1027,12 @@
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\since 6.1
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\overload
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\deprecated [6.10] Use makeReadyRangeFuture() instead
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The QtFuture::makeReadyFuture() method should be avoided because it has an
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inconsistent set of overloads. It will be deprecated in future Qt releases.
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Use QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture() or
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QtFuture::makeReadyRangeFuture() instead.
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Creates and returns a QFuture which already has multiple results set from \a values.
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@ -1009,7 +1009,9 @@ static QFuture<std::decay_t<T>> makeReadyValueFuture(T &&value)
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Q_CORE_EXPORT QFuture<void> makeReadyVoidFuture(); // implemented in qfutureinterface.cpp
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#if QT_DEPRECATED_SINCE(6, 10)
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template<typename T, typename = QtPrivate::EnableForNonVoid<T>>
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QT_DEPRECATED_VERSION_X(6, 10, "Use makeReadyValueFuture() instead")
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static QFuture<std::decay_t<T>> makeReadyFuture(T &&value)
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{
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return makeReadyValueFuture(std::forward<T>(value));
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@ -1019,10 +1021,12 @@ static QFuture<std::decay_t<T>> makeReadyFuture(T &&value)
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// uses makeReadyVoidFuture() and required QFuture<void> to be defined.
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template<typename T>
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QT_DEPRECATED_VERSION_X(6, 10, "Use makeReadyRangeFuture() instead")
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static QFuture<T> makeReadyFuture(const QList<T> &values)
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{
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return makeReadyRangeFuture(values);
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}
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#endif // QT_DEPRECATED_SINCE(6, 10)
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#ifndef QT_NO_EXCEPTIONS
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@ -4078,6 +4078,9 @@ void tst_QFuture::rejectPendingResultOverwrite()
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void tst_QFuture::createReadyFutures()
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{
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#if QT_DEPRECATED_SINCE(6, 10)
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QT_WARNING_PUSH
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QT_WARNING_DISABLE_DEPRECATED
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// using const T &
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{
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const int val = 42;
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@ -4113,6 +4116,8 @@ void tst_QFuture::createReadyFutures()
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QCOMPARE(f.resultCount(), 3);
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QCOMPARE(f.results(), values);
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}
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QT_WARNING_POP
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#endif // QT_DEPRECATED_SINCE(6, 10)
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// test makeReadyValueFuture<T>()
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{
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