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doc,test: fix inspect's sorted compare function

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In V8 7.0, the array sorting algorithm was changed to Timsort, which
is stable. A compare function returning only `true` or `false`
(converted to 0 and 1) cannot work properly.

PR-URL: https://github.com/nodejs/node/pull/22992
Reviewed-By: Ruben Bridgewater <ruben@bridgewater.de>
Reviewed-By: Colin Ihrig <cjihrig@gmail.com>
Reviewed-By: James M Snell <jasnell@gmail.com>
Reviewed-By: Kyle Farnung <kfarnung@microsoft.com>
This commit is contained in:
Michaël Zasso 2018-09-21 10:40:42 +02:00
parent 36bdd19a6b
commit e758d4ab0a
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GPG Key ID: 770F7A9A5AE15600
2 changed files with 2 additions and 2 deletions
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2
doc/api/util.md
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@ -556,7 +556,7 @@ const o1 = {
};
console.log(inspect(o1, { sorted: true }));
// { a: '`a` comes before `b`', b: [ 2, 3, 1 ], c: Set { 1, 2, 3 } }
console.log(inspect(o1, { sorted: (a, b) => a < b }));
console.log(inspect(o1, { sorted: (a, b) => b.localeCompare(a) }));
// { c: Set { 3, 2, 1 }, b: [ 2, 3, 1 ], a: '`a` comes before `b`' }
const o2 = {

2
test/parallel/test-util-inspect.js
View File

@ -1688,7 +1688,7 @@ assert.strictEqual(
assert.strictEqual(
inspect(
{ a200: 4, a100: 1, a102: 3, a101: 2 },
{ sorted(a, b) { return a < b; } }
{ sorted(a, b) { return b.localeCompare(a); } }
),
'{ a200: 4, a102: 3, a101: 2, a100: 1 }'
);