path: simplify code and remove obsolete checks

Either `end` is `-1` or `startPart` is not `0`. Therefore it's
possible to move the conditions in a way that we eliminate a few code
branches.

PR-URL: https://github.com/nodejs/node/pull/25278
Reviewed-By: Michaël Zasso <targos@protonmail.com>
This commit is contained in:
Ruben Bridgewater 2019-01-27 15:35:40 +01:00
parent e750e9583e
commit e68b0d6fb3
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@ -960,22 +960,21 @@ const win32 = {
}
}
if (end !== -1) {
if (startDot === -1 ||
end === -1 ||
// We saw a non-dot character immediately before the dot
preDotState === 0 ||
// The (right-most) trimmed path component is exactly '..'
(preDotState === 1 &&
startDot === end - 1 &&
startDot === startPart + 1)) {
if (end !== -1) {
ret.base = ret.name = path.slice(startPart, end);
}
} else {
ret.name = path.slice(startPart, startDot);
ret.base = path.slice(startPart, end);
ret.ext = path.slice(startDot, end);
}
}
// If the directory is the root, use the entire root as the `dir` including
// the trailing slash if any (`C:\abc` -> `C:\`). Otherwise, strip out the
@ -1380,30 +1379,22 @@ const posix = {
}
}
if (end !== -1) {
const start = startPart === 0 && isAbsolute ? 1 : startPart;
if (startDot === -1 ||
end === -1 ||
// We saw a non-dot character immediately before the dot
preDotState === 0 ||
// The (right-most) trimmed path component is exactly '..'
(preDotState === 1 &&
startDot === end - 1 &&
startDot === startPart + 1)) {
if (end !== -1) {
if (startPart === 0 && isAbsolute)
ret.base = ret.name = path.slice(1, end);
else
ret.base = ret.name = path.slice(startPart, end);
}
ret.base = ret.name = path.slice(start, end);
} else {
if (startPart === 0 && isAbsolute) {
ret.name = path.slice(1, startDot);
ret.base = path.slice(1, end);
} else {
ret.name = path.slice(startPart, startDot);
ret.base = path.slice(startPart, end);
}
ret.name = path.slice(start, startDot);
ret.base = path.slice(start, end);
ret.ext = path.slice(startDot, end);
}
}
if (startPart > 0)
ret.dir = path.slice(0, startPart - 1);