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Fixed a bug in argument sending to get_one_option.

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Fixed documentation for findopt().
Cleaned code a bit.
This commit is contained in:
jani@ua141d10.elisa.omakaista.fi 2005-10-06 22:09:15 +03:00
parent 3af12c4776
commit 770b9ef34d
1 changed files with 32 additions and 11 deletions
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43
mysys/my_getopt.c
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@ -358,7 +358,8 @@ invalid value '%s'\n",
continue; continue;
} }
get_one_option(optp->id, optp, get_one_option(optp->id, optp,
value ? (char*) "1" : disabled_my_option); *((my_bool*) value) ?
(char*) "1" : disabled_my_option);
continue; continue;
} }
argument= optend; argument= optend;
@ -599,16 +600,27 @@ static int setval(const struct my_option *opts, gptr *value, char *argument,
return 0; return 0;
} }
/* /*
function: findopt Find option
Arguments: opt_pattern, length of opt_pattern, opt_struct, first found SYNOPSIS
name (ffname) findopt()
optpat Prefix of option to find (with - or _)
length Length of optpat
opt_res Options
ffname Place for pointer to first found name
Go through all options in the my_option struct. Return number IMPLEMENTATION
of options found that match the pattern and in the argument Go through all options in the my_option struct. Return number
list the option found, if any. In case of ambiguous option, store of options found that match the pattern and in the argument
the name in ffname argument list the option found, if any. In case of ambiguous option, store
the name in ffname argument
RETURN
0 No matching options
# Number of matching options
ffname points to first matching option
*/ */
static int findopt(char *optpat, uint length, static int findopt(char *optpat, uint length,
@ -623,12 +635,21 @@ static int findopt(char *optpat, uint length,
if (!getopt_compare_strings(opt->name, optpat, length)) /* match found */ if (!getopt_compare_strings(opt->name, optpat, length)) /* match found */
{ {
(*opt_res)= opt; (*opt_res)= opt;
if (!count)
*ffname= (char *) opt->name; /* We only need to know one prev */
if (!opt->name[length]) /* Exact match */ if (!opt->name[length]) /* Exact match */
return 1; return 1;
if (!count || strcmp(*ffname, opt->name)) /* Don't count synonyms */ if (!count)
{
count= 1;
*ffname= (char *) opt->name; /* We only need to know one prev */
}
else if (strcmp(*ffname, opt->name))
{
/*
The above test is to not count same option twice
(see mysql.cc, option "help")
*/
count++; count++;
}
} }
} }
return count; return count;